The following is a given equation consisting of two variables x and y.
2y2 = 2x2 + 4x + 2
By dividing the both sides of the equation by 2, we have the following.
y2 = x2 + 2x + 1
The right-hand side of the equation can be factorized as follows.
x2 + 2x + 1 = (x + 1)2
Thus, the given equation is transformed as follows.
y2 = (x + 1)2
This quadratic equation has two distinct solutions of y in terms of x:
y = x + 1 and y = −(x + 1).
Note that there are an infinite number of pairs of x and y that satisfy the given equation.
Therefore, solutions of the given equation are all pairs of x and y that satisfy
at least one of the two linear equations y = x + 1 and y = −(x + 1).
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